# Design IRB 460 for drilling purposes

Sam123
Belgium ✭

I have a question about the IRB 460 robot. I
know this robot is intended as a palletizing robot, but I want to use
this robot for drilling purposes (I already have the robot, so suggesting that I should use another robot for drilling purposes won't help me).

In the
product specification for this robot, I can find the max load and max
moment of inertia, but I suppose that this max load only acts downwards.
Suppose I put a spindle with a drill on the flange, how can I know the
max force that the robot can "push" downwards? With this force I mean
the cutting force of a drill bit that works downwards on a material.

I
thought at first that this force could be calculated like the
following: the max load is 110 kg, which means the max force the robot
can lift is around 1080 N, so I suppose that this is also the max force the robot can push downwards, but is this correct?

Thanks for any help!

## Comments

I am not a mechanical engineer, still I suspect you will find the 460 will issue errors related to torque at different compression values depending the tool Z value & on how close to the base of the manipulator the test occurs.